* Problem Link: https://lightoj.com/problem/opposite-task
*Solution:
#include <stdio.h>
int main() {
int a,i,b;
scanf("%d",&a);
for(i=0;i<a;i++){
scanf("%d",&b);
if(b>10){
if(b%2==0){
printf("%d %d\n",(b/2),(b/2));
}
else printf("%d %d\n",((b+1)/2),(((b+1)/2)-1));
}
else printf("%d %d\n",(b-b),(b));
}
return 0;
}
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